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Cplusplus is for the weak

Cplusplus is for the weak

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19 Comments


  1. MrMo1

    November 15, 2017 at 6:03 am

    c += 1;

    Reply

  2. McNerdius

    November 15, 2017 at 6:03 am

    c = ++c;

    Reply

  3. ExeusV

    November 15, 2017 at 6:03 am

    but tag it as NSFW dude

    Reply

  4. Ta11ow

    November 15, 2017 at 6:03 am

    `c = c + (c / c)`

    Reply

  5. ssorc3

    November 15, 2017 at 6:03 am

    int temp = c;
    temp = temp + 1;
    c = temp;

    Reply

  6. NelsonBelmont

    November 15, 2017 at 6:03 am

    INT_1 = 1;
    c = c + INT_1;

    Reply

  7. BenJoey

    November 15, 2017 at 6:03 am

    c=increase(c, 1);

    int increase (int a, int b) {
    c=a+b;
    return c;}

    Reply

  8. sin2pifx

    November 15, 2017 at 6:03 am

    int add(int x, int y) {
    return y == 0? x: add(x ^ y, (x & y) << 1);
    }

    (parallel bitwise addition with carry; not originally mine)

    Reply

  9. diamondflaw

    November 15, 2017 at 6:03 am

    c+=c==c

    Reply

  10. Scooxstad

    November 15, 2017 at 6:03 am

    inb4 new shitposting meta

    Reply

  11. blore40

    November 15, 2017 at 6:03 am

    COBOL says “ADD 1 TO C.“

    Reply

  12. hue363

    November 15, 2017 at 6:03 am

    c = c + is_even(2);

    Reply

  13. HACKERcrombie

    November 15, 2017 at 6:03 am

    ASM anyone?

    Reply

  14. iampig

    November 15, 2017 at 6:03 am

    C.operator=(C.operator+(1));

    Reply

  15. scatters

    November 15, 2017 at 6:03 am

    std::exchange(c, -~c)

    You want to get out the old value while storing the incremented value.

    Reply

  16. SteeleDynamics

    November 15, 2017 at 6:03 am

    Not shitpost: `++c `

    Shitpost: `++–++–++c`

    Reply

  17. awesome2dab

    November 15, 2017 at 6:03 am

    Double a = 1
    c = c + (int)(String.valueOf(a));

    Reply

  18. LocalHero457

    November 15, 2017 at 6:03 am

    #define CPP C++
    for (int C=0; C<457; CPP)
    printf(“%dn”, C);

    Reply

  19. explodingpear

    November 15, 2017 at 6:03 am

    + h1cc

    Reply

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